WebIn a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C Answer: B) 20 m Explanation: Subject: Races and Games - Quantitative Aptitude - Arithmetic Ability … WebOct 25, 2024 · A covers 100 meter in same time as B covers (100-10) meter and C covers (100-28) meter. Using unitary method, we can find out the head-start that B can give to C. …
In a 100 m race, A can give B 10 m and C 28 m. In Races and Games
WebMar 21, 2024 · Solution: According to the question, B covers 28 m in 7 seconds. => B’s speed = 28 / 7 = 4 m/s => Time required by B to complete 100 m = 100 / 4 = 25 s Now, A needs 7 s less than B to complete the race. => Time required by A = 25 – 7 = 18 s. Q2. In a 100 m race, A can give a start of 4 m to B and 6.4 m to C. WebAug 9, 2024 · Sol: When A finished the race, B is 14m ahead of C ad B has to travel 20m to finish the race. When B finished the race, he is ahead of C by 21m. ∴ , when B covered 20m, then the difference between the distance covered by B and C is 7m. ∴ to have the difference of 21m between the distances covered by B and C, B has to cover 60m. ∴ the ... high end restaurants in lexington ky
In a 100 m race A can beat B by 25 - Examveda
WebIn a 100m race, A can give B 10m and C 28m. In the same race B can give C: S Linear & Circular Races A 18 m B 20 m C 27 m D 9 m Show Answer RELATED MCQ'S Three cyclists … WebNov 30, 2024 · (B) 8 m/sec (C) 10 m/sec (D) 12.5 m/sec (E) 20 m/sec Solution: When B gets a head start of 20 sec, he falls short by 40m. However, when he gets the head start of 25 sec, he finished right alongside A. This implies, that B can run 40m in 5 sec. Hence speed of B is 8m/s. when he gives B a start of 25 seconds - B got the head start of 200m. Hence ... Webin the video. He started with the formula: vi + (delta t) (a) = vf. 5 + (4s) (2 m/s^2) = vf. 5 m/s + 8 m/s = vf. 13 m/s = vf. So 8 m/s = (delta t) (a) = vf - vi = delta v. This 8 m/s is the change in velocity (v increased by 2 m/s every second, for 4 seconds). That's why 8 m/s also became the height of the triangle, since the bottom of the ... high end restaurants in oxford